8s^2-46s+11=0

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Solution for 8s^2-46s+11=0 equation:



8s^2-46s+11=0
a = 8; b = -46; c = +11;
Δ = b2-4ac
Δ = -462-4·8·11
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-42}{2*8}=\frac{4}{16} =1/4 $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+42}{2*8}=\frac{88}{16} =5+1/2 $

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